52/12 = 4 and 1/3
In a standard deck of 52 playing cards, the number of combinations of 3 cards can be calculated using the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). For 3 cards from 52, it is ( C(52, 3) = \frac{52!}{3!(52-3)!} = \frac{52 \times 51 \times 50}{3 \times 2 \times 1} = 22,100 ). Thus, there are 22,100 different combinations of 3 cards in a deck.
no people it 3 doesn't go into 52
13 can go into 45 a total of 3 times, since 13 multiplied by 3 equals 39. When you multiply 13 by 4, it equals 52, which exceeds 45. Therefore, the largest whole number of times 13 can fit into 45 is 3.
If you group the division pairs: (24/6) x (3/52) = 4 x 3/52 = 12/52 = 3/13 If you go sequentially, it is the same in this case. But if you arrange them [24 / (6 x 3)] / 52, you get a different result, which is 1/39.
52 times.
About 3.9 times or 3 times with a remainder of 52.
7 times with remainder 3.7 times with remainder 3.
52/12 = 4 and 1/3
three goes into 52 164 times
3 x 50 = 150 3 x 2 = 6 50 + 2 = 52
7 times with a remainder of 3
Well, isn't that a happy little math problem! If you take 52 and divide it by 16, you'll find that it goes in 3 times with a remainder of 4. Remember, there are no mistakes in math, just happy little accidents!
51 ÷ 3 = 17 Therefore 3 goes into 51 17 times
In a standard deck of 52 playing cards, the number of combinations of 3 cards can be calculated using the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). For 3 cards from 52, it is ( C(52, 3) = \frac{52!}{3!(52-3)!} = \frac{52 \times 51 \times 50}{3 \times 2 \times 1} = 22,100 ). Thus, there are 22,100 different combinations of 3 cards in a deck.
8 with a remainder of 4 Or if you want a decimal answer its 8.6666... repeating
no people it 3 doesn't go into 52