How many tons of sand do you need to cover 14000 sq ft 2 inches deep?

Answer 1

Approximately 117.5 tons of dry sand.

I willl use 1602 kg/m3 as the density of the sand. (See http://www.simetric.co.uk/si_materials.htm)

We need common units, so first I will convert 1602 kg/m3 to lbs/cubic yard.

1602 kg/m3 = 1602 kg/m3 * (2.2 lb/kg) * (1m3/1.093 cu yds) = (1602*2.2)/1.093 = 2721 lbs/cu yard

Now figure out the volume of sand you need (in cubic yards).

volume = (14000 sq ft)*(2 in) = ((14000/9) sq yds)*((2/36) yds) = (14000/9)*(2/36) yds = 86.4 cu yds

weight = density*volume=2721*86.4 lbs = 235094 lbs = 235094/2000 tons = 117.5 tons