The word "PRETTY" consists of 6 letters, with the letter "T" appearing twice. To find the number of unique arrangements, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2!} ), where ( n ) is the total number of letters, and ( n_1, n_2, ) etc., are the frequencies of the repeated letters. Here, ( n = 6 ) and the frequency of "T" is 2. Thus, the number of unique arrangements is ( \frac{6!}{2!} = \frac{720}{2} = 360 ).
12
The word "OPAL" consists of 4 distinct letters. The number of unique arrangements of these letters can be calculated using the factorial of the number of letters, which is 4!. Therefore, the total number of unique arrangements is 4! = 24.
The number of different ways to arrange 4-letter words depends on whether the letters are unique or not. If all 4 letters are unique, the arrangements can be calculated using factorial notation: 4! (4 factorial), which equals 24. If some letters are repeated, the formula adjusts accordingly, dividing by the factorial of the counts of the repeated letters.
The word "party" consists of 5 unique letters. The number of ways to arrange these letters is calculated using the factorial of the number of letters, which is 5!. Therefore, the total number of arrangements is 5! = 120.
25 times
12
360
60 ways.
120 ways
The word "OPAL" consists of 4 distinct letters. The number of unique arrangements of these letters can be calculated using the factorial of the number of letters, which is 4!. Therefore, the total number of unique arrangements is 4! = 24.
The number of different ways to arrange 4-letter words depends on whether the letters are unique or not. If all 4 letters are unique, the arrangements can be calculated using factorial notation: 4! (4 factorial), which equals 24. If some letters are repeated, the formula adjusts accordingly, dividing by the factorial of the counts of the repeated letters.
40
The word "party" consists of 5 unique letters. The number of ways to arrange these letters is calculated using the factorial of the number of letters, which is 5!. Therefore, the total number of arrangements is 5! = 120.
There are 4 distinguishable letters in the word fish, so there is 4! or 24 different ways can you arrange the letters in the word fish.
24 ways.
25 times
10080