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6 faces 12 edges 8 vertices
It can't exist:The sum of the exterior angles of any polygon is 360o.For a regular polygon:exterior_angle x number_of_sides = 360o→ number_of_sides = 360o ÷ exterior_angle→ number_of_sides = 360o ÷ 108o= 31/3but the number of sides number be a whole number, ergo a regular polygon with an exterior angle of 108o cannot exist.If you meant: Each interior angle of a regular polygon is 108o; how many sides doe the polygon have?Then:exterior_angle + interior_angle = 180o→ exterior_angle = 180o - interior_angle= 180o - 108o= 72o→ number_of_sides = 360o ÷ 72o= 5The polygon is a regular pentagon.
A dodecagon has 12 sides
67
Lets see 1, 2,3,4,5,6,7,8,9,10,11,12 12