A 10-sided shape, also known as a decagon, has 10 vertices. Each vertex is a point where two sides of the shape meet. In general, an n-sided polygon has n vertices.
A ten sided decagon has 10 vertices
A decagon has 10 vertices and 10 sides.It has ten cornersA decagon is a 10 sided polygon that has 10 vertices
To determine how many heptagons can be formed by joining the vertices of a 10-sided polygon, we can use the combination formula. Specifically, we need to choose 7 vertices from the 10 available. This is calculated as ( \binom{10}{7} ), which is equal to ( \binom{10}{3} ) (since choosing 7 vertices to include is the same as choosing 3 vertices to exclude). Thus, ( \binom{10}{3} = \frac{10!}{3!(10-3)!} = 120 ). Therefore, 120 heptagons can be drawn by joining the vertices of a 10-sided polygon.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. 10 vertices
35 diagonals
A ten sided decagon has 10 vertices
There Are 10 Vertices.
A decagon has 10 vertices and 10 sides.It has ten cornersA decagon is a 10 sided polygon that has 10 vertices
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Oh, dude, a decagon has 10 sides, so it also has 10 vertices. As for faces, well, a decagon is a 2D shape, so it technically only has one face. But hey, who's counting, right?
To determine how many heptagons can be formed by joining the vertices of a 10-sided polygon, we can use the combination formula. Specifically, we need to choose 7 vertices from the 10 available. This is calculated as ( \binom{10}{7} ), which is equal to ( \binom{10}{3} ) (since choosing 7 vertices to include is the same as choosing 3 vertices to exclude). Thus, ( \binom{10}{3} = \frac{10!}{3!(10-3)!} = 120 ). Therefore, 120 heptagons can be drawn by joining the vertices of a 10-sided polygon.
A prism with an n-sided base will have 2n vertices, n + 2 faces, and 3n edges. 10 vertices
A 6 sided hexagon has 6 vertices and so 3 hexagons will have 3*6 = 18 vertices
so good
A 10-sided shape is a decagon.
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10 sided shape: Decagon