"Watt" is a rate of using energy.
"4 kW" means 4,000 watts.
"4 kW for 6 hours" means 4,000 watts for 6 hours.
If you use energy at the rate of 4 kW for 6 hours, then altogether you use
24 kilowatt-hours, or 24,000 watt-hours, or 86,400,000 joules.
4 megawatts = 4,000,000 (4 million) watts Mega means Million.
Yes, but.... KWH = KW * H So any numbers that satisfy this equation are also one KWH. For instance: * 250 watts for 4 hours * 500 watts for 2 hours * 1000 watts for 1 hour * 2000 watts for 0.5 hours * 4000 watts for 15 minutes * etc. Keep in mind that kilo- means thousands, so KW means thousands of watts ( 1KW = 1000W).
To calculate the amperage for 4 kW, you would need to know the voltage of the circuit. However, assuming a standard voltage of 120V, you can use the formula: amps = watts / volts. Therefore, for 4 kW at 120V, the amperage would be approximately 33.33 amps.
Max 5 kW but it could be less for certain types of load, for example a motor. Most motors have a power factor of less than 1 . . . . 0.8 for example, which would give 4 kW from 5 kVA.
To calculate the energy used by a 12 volt landscape light in 4 hours, you would need to know the wattage of the light. For example, if the light is 10 watts, it would use 10 watts x 4 hours = 40 watt-hours.
To convert kilowatts to watts, multiply by 1000. Therefore, 75 kilowatts is equal to 75,000 watts.
About 3/4 kW
1 kW = 1000 w So 40 W / 1000 W = 0.04 kW As soon at the light is turned on, the lamp starts to use energy at the rate of 40 W = 0.04 kW. If you leave it on for 100 hours it will have used up 0.04 x 100 = 4 kWh
First, convert the heater's power usage to kilowatts: 260 watts = 0.26 kilowatts. Next, calculate the energy consumption: 0.26 kW * 4 hours = 1.04 kWh. Finally, multiply the energy consumption by the cost per kWh: 1.04 kWh * $0.20/kWh = $0.208. So, running a 260 watt heater for 4 hours would cost approximately 20.8 cents.
Add up all the individual watts, convert everything to kilowatts, then multiply by the number of hours.
Most places in the US have what we call 4-5 'full sun hours' per day, which takes into account weather and seasonal shifts. So if you need 3300kwh per month, you'd need about 110 kw-hrs per day / 4.5 sun hours /day = 24 kilowatts. 24 kilowatts equals 24,000 watts, and you divide by .80 for efficiencies and voltage losses = 30,000 watts. so 30,000 dvidided by 250 = 120 panels.
3/4 of watts