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To determine how many ways 14630 can be expressed as a product of two numbers, we first need its prime factorization. The prime factorization of 14630 is (2 \times 5 \times 1463). The number of divisors can be calculated from the exponents of the prime factors; since (2^1, 5^1, \text{ and } 1463^1) each have an exponent of 1, the total number of divisors is ((1+1)(1+1)(1+1) = 2 \times 2 \times 2 = 8). Each pair of divisors ( (d, \frac{14630}{d}) ) gives a product of 14630, so the number of unique pairs is half of the total number of divisors, leading to 4 ways to express 14630 as a product of two numbers.

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4w ago

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