Do 6 X 6 it equals 36..that's how many
once
To find the number of ways 3 boys and 2 girls can stand in a row such that the girls are not next to each other, first calculate the total arrangements without restrictions, which is (5!) (for 5 individuals), yielding 120 arrangements. Next, calculate the arrangements where the two girls are together by treating them as a single unit, resulting in (4!) arrangements for the group and (2!) arrangements for the girls within that group, giving (4! \times 2! = 48). Finally, subtract the restricted arrangements from the total: (120 - 48 = 72). Thus, there are 72 ways for the boys and girls to stand so that the girls are not next to each other.
6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.
25
What r u talking about???
boy girl boy girl boy girl boy
6 ways
There are 56 ways.
once
boys and girls are the same in many ways yet different but i really got to say is i think girls are better at understanding things
In many ways, yes; in just a few, no.
6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.
2 boys from 6 = 6*5/2 = 15 ways 2 girls from 3 = 3*2/2 = 3 ways All in all, 15*3 = 45 ways.
25
What r u talking about???
6!*7p4
All girls are not pretty and all boys are not ugly. Everyone is beautiful in their own unique ways.