0
What else can I help you with?
How many ways can a family have 3 boys and 2 girls?
once
How many ways can 3 boys and 2 girls stand in a row so that the two girls are not next to each other?
To find the number of ways 3 boys and 2 girls can stand in a row such that the girls are not next to each other, first calculate the total arrangements without restrictions, which is (5!) (for 5 individuals), yielding 120 arrangements. Next, calculate the arrangements where the two girls are together by treating them as a single unit, resulting in (4!) arrangements for the group and (2!) arrangements for the girls within that group, giving (4! \times 2! = 48). Finally, subtract the restricted arrangements from the total: (120 - 48 = 72). Thus, there are 72 ways for the boys and girls to stand so that the girls are not next to each other.
In how many ways can 3 girls and 5 boys be arranged in a row so that all the 3 girls are together?
6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.
There are five girls and five boys at a party In how many ways can they be seated in a row of six?
25
In how many different ways could a family have 4 boys and 4 girls?
What r u talking about???
How many ways can four boys and three girls stand in a line so that no two boys or two girls are next to each other?
boy girl boy girl boy girl boy
How many ways to sit sit 3 boys and 2 girls?
6 ways
How many ways can you have 8 children with 5 boys and 3 girls?
There are 56 ways.
How many ways can a family have 3 boys and 2 girls?
once
How many ways can 3 boys and 2 girls stand in a row so that the two girls are not next to each other?
To find the number of ways 3 boys and 2 girls can stand in a row such that the girls are not next to each other, first calculate the total arrangements without restrictions, which is (5!) (for 5 individuals), yielding 120 arrangements. Next, calculate the arrangements where the two girls are together by treating them as a single unit, resulting in (4!) arrangements for the group and (2!) arrangements for the girls within that group, giving (4! \times 2! = 48). Finally, subtract the restricted arrangements from the total: (120 - 48 = 72). Thus, there are 72 ways for the boys and girls to stand so that the girls are not next to each other.
What can boys do but girls can do better?
boys and girls are the same in many ways yet different but i really got to say is i think girls are better at understanding things
Are girls capable like boys?
In many ways, yes; in just a few, no.
In how many ways can 3 girls and 5 boys be arranged in a row so that all the 3 girls are together?
6ways. represent boys as<.> girls as</> 1=///..... 2=.///.... 3=..///... 4=...///.. 5=....///. 6=...../// here may be the boys can arranged different ways. 5 boys arranged 5! = 120 ways. In 120 times, each time added girls 6 ways like the above way. so answer is 6*120 = 720 ways we can arrange.
From a group of 6 boys and 3 girls an afterschool reading club of 2 boys and 2 girls is selected How many such clubs are possible?
2 boys from 6 = 6*5/2 = 15 ways 2 girls from 3 = 3*2/2 = 3 ways All in all, 15*3 = 45 ways.
There are five girls and five boys at a party In how many ways can they be seated in a row of six?
25
In how many different ways could a family have 4 boys and 4 girls?
What r u talking about???
In how many ways six boys and four girls can be arranged in one rope so that no two girls can sit together?
6!*7p4
