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How many ways can a group of 12 choose committee of 9?
12C9 = 220
How many different ways are there for an admission officer to select a group of 8 college candidates from a group of 12 applicants for an interview?
15
How many ways can 4 people be chosen from a group of 12?
The number of ways to choose 4 people from a group of 12 can be calculated using the combination formula, which is given by ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ). Here, ( n = 12 ) and ( r = 4 ). Thus, ( \binom{12}{4} = \frac{12!}{4!(12-4)!} = \frac{12!}{4! \cdot 8!} = \frac{12 \times 11 \times 10 \times 9}{4 \times 3 \times 2 \times 1} = 495 ). Therefore, there are 495 ways to choose 4 people from a group of 12.
How many different ways can 1235 be?
12
How many ways can 12 true and false be arrange?
Assuming there are 12 statements that can be true or false, there are 212 = 4096 ways.
How many ways can a group of 12 choose committee of 9?
12C9 = 220
How many ways can a group of 3 be selected from a group with 12 members?
12C3 = 12*11*10/(3*2*1) = 220
How many different ways are there for an admission officer to select a group of 8 college candidates from a group of 12 applicants for an interview?
15
How many ways can you match 12 questions with 12 answers?
144 ways
How many ways can 4 people be chosen from a group of 12?
The number of ways to choose 4 people from a group of 12 can be calculated using the combination formula, which is given by ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ). Here, ( n = 12 ) and ( r = 4 ). Thus, ( \binom{12}{4} = \frac{12!}{4!(12-4)!} = \frac{12!}{4! \cdot 8!} = \frac{12 \times 11 \times 10 \times 9}{4 \times 3 \times 2 \times 1} = 495 ). Therefore, there are 495 ways to choose 4 people from a group of 12.
How many groups can be made with 12 boys and 8 girls if the same number of girls and boys are in each group?
the answer will be 4
How many possible ways can a committee of eight people can be selected from a group of 14 people?
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
How many ways can 12 be divided into equal groups?
You can have one group of 12, two groups of 6, three groups of 4, four groups of 3, six groups of 2, or twelve groups of one. If you count "one group of 12", then there are six different ways. If not, then there are five. To be awkward, the way the question is put, there is an infinity of ways. Choose any n, where n is any positive integer number you like and you can have n groups each one with 12/n in it.
How many different ways can 1235 be?
12
40 times 12?
There are many ways
How many ways can 12 true and false be arrange?
Assuming there are 12 statements that can be true or false, there are 212 = 4096 ways.
In how many ways can 4 people be chosen from a group of 12 people and arranged in a straight line?
First in line can be any of the 12, second can be any of the remaining 11, third any of 10 and fourth any of 9 so 12 x 11 x 10 x 9 ie 11880 different ways
