12C9 = 220
15
12
Assuming there are 12 statements that can be true or false, there are 212 = 4096 ways.
First in line can be any of the 12, second can be any of the remaining 11, third any of 10 and fourth any of 9 so 12 x 11 x 10 x 9 ie 11880 different ways
12C9 = 220
12C3 = 12*11*10/(3*2*1) = 220
15
144 ways
You can have one group of 12, two groups of 6, three groups of 4, four groups of 3, six groups of 2, or twelve groups of one. If you count "one group of 12", then there are six different ways. If not, then there are five. To be awkward, the way the question is put, there is an infinity of ways. Choose any n, where n is any positive integer number you like and you can have n groups each one with 12/n in it.
the answer will be 4
There are many ways
12
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
Assuming there are 12 statements that can be true or false, there are 212 = 4096 ways.
First in line can be any of the 12, second can be any of the remaining 11, third any of 10 and fourth any of 9 so 12 x 11 x 10 x 9 ie 11880 different ways
4!/2!=12 ways