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How many ways can a group of 12 choose committee of 9?
12C9 = 220
How many way can a group of 7 choose a committee of 4?
Any 4 from 7 = 35 ways
How many ways can a teacher choose 2 students from a group of 4 students?
7
How many different ways can 4 kids be chosen to serve on a committee from a group of 30 kids?
40 x 39 x 38 x 37 = 2193360
How many ways can a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students?
For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!
How many ways can a group of 12 choose committee of 9?
12C9 = 220
How many way can a group of 7 choose a committee of 4?
Any 4 from 7 = 35 ways
How many ways can a group of 7 chose a committee of 4?
7*6*5*4/(4*3*2*1) = 35 ways
How many ways can a teacher choose 2 students from a group of 4 students?
7
In how many ways can a 3-person committee be selected from a group of 4?
-1
How many different ways can the letters of committee be arranged?
There are 45360 ways.
How many different ways can 4 kids be chosen to serve on a committee from a group of 30 kids?
40 x 39 x 38 x 37 = 2193360
How many possible ways can a committee of eight people can be selected from a group of 14 people?
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
How many ways can a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students?
For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!
How many subcommittees does the house ways and means committee have?
house has 106
In how many ways can a chairperson and a vice chairperson be selected from a committee of 18 senators?
18x17= 306 ways
How many different ways can 1 committee of 5 students be selected from a class of 25?
53,130 ways.
