12C9 = 220
Any 4 from 7 = 35 ways
7
40 x 39 x 38 x 37 = 2193360
For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!
12C9 = 220
Any 4 from 7 = 35 ways
Well, honey, if you want a committee with at least 3 educators out of 5 members, you can choose 3 educators out of 8 in 8 choose 3 ways, and then fill the remaining 2 spots with any of the remaining educators or accountants. So, that gives you 8 choose 3 * 5 choose 2 ways, which is 56 * 10 = 560 ways to create your sassy little committee.
7*6*5*4/(4*3*2*1) = 35 ways
7
-1
There are 45360 ways.
40 x 39 x 38 x 37 = 2193360
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!
house has 106
18x17= 306 ways