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If the first woman sits at an end, there is only the seat next to her where the second woman can sit. There are 2 such chairs, giving 2 × 1 = 2 possible sittings.

If the first woman doesn't sit at the end, the second woman can sit either side of her in one of 2 chairs. There are 5 - 2 = 3 such chairs, giving, 2 × 3 = 6 possible sittings.

Thus there are 2 + 6 = 8 possible sitting positions of the women.

For each of these there are 3 empty chairs which the man can occupy,

Thus there are 8 × 3 = 24 possible ways that 2 women and 1 man can sit on a row of 5 empty chairs if the two women must sit together.

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