87,178,291,200 ways.
That is factorial 14 or expressed as 14! = 14*13*12*10*9*8*7*6*5*4*3*2*1
With just 4 people there are 4*3*2*1 = 24 ways
With 5 people there are 5*4*3*2*1 = 120 ways
etc.etc.
There are 24 ways to arrange 4 people in a row.
40320
7! = 5040 ways.
The number of ways to arrange ( n ) people in a row is given by ( n! ) (n factorial), which is the product of all positive integers up to ( n ). For example, if you have 3 people, the arrangements would be ( 3! = 3 \times 2 \times 1 = 6 ) ways. Thus, to find the number of arrangements for any given number of people, simply calculate the factorial of that number.
8 ways
There are 24 ways to arrange 4 people in a row.
40320
24
7! = 5040 ways.
you are arranging 70 plants in a rectangular garden with the same number in each row how many ways can you arrange the garden
They can be arranged 5! or 120 ways.
The number of ways to arrange ( n ) people in a row is given by ( n! ) (n factorial), which is the product of all positive integers up to ( n ). For example, if you have 3 people, the arrangements would be ( 3! = 3 \times 2 \times 1 = 6 ) ways. Thus, to find the number of arrangements for any given number of people, simply calculate the factorial of that number.
8 ways
i think a total of 6 but i am not sure
There are 4*3*2*1 = 24 ways. However, if you consider ABCD as the same as DCBA - same neighbours, but left and right swapped - then there are only half as many.
6! = 6 factorial = 1x2x3x4x5x6 = 720
Five people are to be arranged in a row to have their picture taken. In how many ways can this be done?