Assuming that by "arrange" you mean "order" (if you really mean "arrange", there are infinitely many possible ways to arrange even just two objects; you could separate them by 1 inch, or by 2 inches, or by 3.14159265... inches, and that's without even getting into left vs. right or above vs. below or at an angle of x degrees from horizontal) ...
You can choose any of the 6 to be first, any of the remaining 5 to be second, any of the remaining 4 to be third, and so on, down to the last one where you have no choice because it's the only one left.
That means there are 6x5x4x3x2(x1), or 6! = 720 possible orderings.
6 to the power of 6 so 6x6x6x6x6x6=46,656
6
6! = 720
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
6
9×8×7×6×5=15,120
6 to the power of 6 so 6x6x6x6x6x6=46,656
6
6! = 720
In a line in 6! = 6*5*4*3*2*1 = 720 ways.
3*2*1 = 6 ways.
30 ways.
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
The word "onomatopoeia" has 11 letters, with 6 vowels and 5 consonants. Therefore, there are 11!/(6!5!) = 33,120 ways to arrange the word "onomatopoeia".
6! = 6*5*4*3*2*1 = 720
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.