Best Answer

There are 22 ways to make change from a dollar using nickels, dimes, and quarters.

1. 4 q

2. 10 d

3. 20 n

4. 2 q , 5 d

5. 3 q , 2 d , 1 n

6. 1 q , 7 d, 1 n

7. 9 d, 2 n

8. 8 d, 4 n

9. 7 d, 6 n

10. 6 d , 8 n

11. 5 d , 10 n

12. 4 d , 12 n

13. 2 d , 16 n

14. 1 d , 18 n

15. 5 n , 3 q

16. 3 n , 1 q , 6 d

17. 7 n , 1 q , 4 d

18. 9 n , 1 q , 3 d

19. 11 n , 1 q , 2 d

20. 13 n , 1 q , 1 d

21. 14n , 3 d

22. 15n , 1 q

Q: How many ways can you make change for a dollar using nickels dimes andor quarters?

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translation of graphs , try that :)

help me please

That would be a pleasant diversion. Sadly, however,you've neglected to give us the "given" set.

Let's suppose you mean How many vertices does a nonahedron have? And the answer is, It depends. A nonahedron is a solid with nine faces. There is no regular nonahedron (look up "Regular solid" anywhere, say on Wikipedia). You could make a nonahedron bytaking a cube (6 square faces, 12 vertices) and slicing off 3 of the vertices to add 3 triangular faces (and making their adjacent original faces no longer square); this solid has 16 verticestaking a regular octahedron (8 triangular faces, 6 vertices) and slicing off one vertex to add one square face (the four adjacent original faces are now trapezoids): 9 verticesshaving down 5 of the edges to add 5 long narrow faces... and I can't visualize this one well enough to count the verticesor slicing off all 4 vertices (adding 4 small triangular faces and making the original faces hexagonal) and shaving one edge (adding a long rectangular face and changing the faces at the ends of the original edge from small triangles to trapezoids): 14 vertices, if I've got it right.taking a tetrahedron (4 faces, 6 edges, 4 vertices) andor countless other ways, yielding many different counts of vertices. ... Well, I'm sure they could be counted, but I'm not about to do it now.

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