2*2-*2*3 = 24 or as 23*3 = 24
Two
4
To determine the number of prime numbers between 1 and 8888888888888888888888888888888888888888888888, we can use the Prime Number Theorem. This theorem states that the density of prime numbers around a large number n is approximately 1/ln(n). Therefore, the number of prime numbers between 1 and 8888888888888888888888888888888888888888888888 can be estimated by dividing ln(8888888888888888888888888888888888888888888888) by ln(2), which gives approximately 1.33 x 10^27 prime numbers.
39!
Since there are infinitely many primes, there are infinitely many numbers that are products of 3 primes.
This can be an extension to the proof that there are infinitely many prime numbers. If there are infinitely many prime numbers, then there are also infinitely many PRODUCTS of prime numbers. Those numbers that are the product of 2 or more prime numbers are not prime numbers.
Two
I'm not sure what you mean. But the factorization of a composite number into prime factors is unique, up to the ordering of the primes.
4
To determine the number of prime numbers between 1 and 8888888888888888888888888888888888888888888888, we can use the Prime Number Theorem. This theorem states that the density of prime numbers around a large number n is approximately 1/ln(n). Therefore, the number of prime numbers between 1 and 8888888888888888888888888888888888888888888888 can be estimated by dividing ln(8888888888888888888888888888888888888888888888) by ln(2), which gives approximately 1.33 x 10^27 prime numbers.
39!
Since there are infinitely many primes, there are infinitely many numbers that are products of 3 primes.
The prime factors of 200 are 2 and 5 or as a product of its prime factors 2*2*2*5*5 = 200
Two of them and as a product of its prime factors: 2*2*2*2*5*5*5 = 2000
11*2 = 22
There are infinitely many prime numbers and the product of any four of them will meet the requirements. For example, 11*37*97*983 = 38,807,857
10x5 and 1x50