The first person has a choice of 6 seats, the second one has only 5 choices, the third one 4 choices, the fourth one 3 choices, the fifth one 2 choices a, and the sixth person has to take the one seat that is left.
So the answer is 6! or 6x5x4x3x2x1 = 720 ways.
In a line, in 6 ways. Around a table, in 2 ways.
To seat 5 men and 5 women alternately at a round table, we can fix one person to eliminate symmetrical arrangements. This leaves us with 4 men and 5 women to arrange. The men can be arranged in (4!) ways and the women in (5!) ways. Therefore, the total number of arrangements is (4! \times 5! = 24 \times 120 = 2880).
720
When seating 4 Knights at 4 empty seats around a round table, we can fix one Knight in one seat to eliminate the rotations, effectively reducing the problem to arranging the remaining 3 Knights in the remaining 3 seats. The number of ways to arrange 3 Knights is given by 3! (3 factorial), which equals 6. Thus, there are 6 different ways for the 4 Knights to sit at the Round Table.
give 2 ways of presenting data
In a line, in 6 ways. Around a table, in 2 ways.
There are many ways in which you could greet a guest. You could always greet a guest with a simple hello.
In how many ways can five children sit at round table?
Hunt seat, saddle seat, bareback, sidesaddle, western. that's all i can think of.
(n-1)! ways 5 people, so 4! ways I do not believe that answer is correct. Look at it this way: Let the first person sit anywhere. Then the remaining 4 people can be seated in 4! (4 factorial = 4 * 3 * 2 * 1) Therefore 4! = 24 ways of seating 5 people around a circular table.
6 i think
There are a great many ways in which you could repair a small burn in your car seat. You could patch it.
There are many ways to sign the guest book at a wedding. Most write a small note of congratulations and then sign their name.
6 different ways
To seat 5 men and 5 women alternately at a round table, we can fix one person to eliminate symmetrical arrangements. This leaves us with 4 men and 5 women to arrange. The men can be arranged in (4!) ways and the women in (5!) ways. Therefore, the total number of arrangements is (4! \times 5! = 24 \times 120 = 2880).
students can be seated in 16 diffrent ways. multiply or draw a table. * * * * * Unfortunately, that is an incorrect answer. The correct answer is 4*3*2*1 = 24 ways. For the first seat, on the left, you can pick any one of the 4 students. For the next seat, you have only three students so you have 3 choices. So the number of ways of filling the first two seats is 4*3. Continue the process.
720