To arrange 3 distinct items, you can use the factorial of the number of items, which is calculated as 3! (3 factorial). This equals 3 × 2 × 1 = 6. Therefore, there are 6 different ways to arrange 3 distinct things.
4! = 4*3*2*1 = 24 ways
The answer is 50P3 = 50*49*48/(3*2*1) = 117,600
To find the number of ways to arrange 6 things 3 at a time, you can use the permutation formula, which is given by ( P(n, r) = \frac{n!}{(n-r)!} ). For this case, ( n = 6 ) and ( r = 3 ), so it becomes ( P(6, 3) = \frac{6!}{(6-3)!} = \frac{6!}{3!} = \frac{720}{6} = 120 ). Therefore, there are 120 ways to arrange 6 things 3 at a time.
4! 4 * 3 * 2 = 24 ways ==========
3! = 1 x 2 x 3 = 6 ways.
4! = 4*3*2*1 = 24 ways
24, 1*2*3*4
6 -- abc, acb, bac, bca, cab, cba
In a line in 6! = 6*5*4*3*2*1 = 720 ways.
The answer is 50P3 = 50*49*48/(3*2*1) = 117,600
To find the number of ways to arrange 6 things 3 at a time, you can use the permutation formula, which is given by ( P(n, r) = \frac{n!}{(n-r)!} ). For this case, ( n = 6 ) and ( r = 3 ), so it becomes ( P(6, 3) = \frac{6!}{(6-3)!} = \frac{6!}{3!} = \frac{720}{6} = 120 ). Therefore, there are 120 ways to arrange 6 things 3 at a time.
How many different ways can we arrange 9 objects taken 3 at a time?
4! 4 * 3 * 2 = 24 ways ==========
The answer is 5 factorial or 5*4*3*2*1 or 120
3! = 1 x 2 x 3 = 6 ways.
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
3*2*1 = 6 ways.