There are factor trees, fireworks, rainbows, etc., but those are just differences in notation. The unique prime factorization of 260 is 2 x 2 x 5 x 13.
11 x 13 = 143 3 x 5 x 13 = 195 2 x 2 x 5 x 13 = 260
2 x 2 x 3 x 3 x 5 x 7 = 1260
Prime factorization of:260 : 2 x 2 x 5 x 13150: 2 x .....5x.......3 x 5=================GCF: 2 x.....5GCF: 2 x 5 = 10
2 x 2 x 3 x 3 x 5 x 7 = 1260
No, prime numbers must have exactly two divisors which result in an integer dividend; these numbers are one (1) and the number itself. Since 260 is an even number it has two (2) as a such a divisor. Thus, it has more than two and is not prime.
The prime factorization of 260 in exponential form is written as: 22 x 5 x 13
22*5*13 = 260
The GCF of 143, 195, and 260 is 13 The prime factorization of 143 is 11*13. The prime factorization of 195 is 13*15. The prime factorization of 260 is 2*2*5*13 So the GCF is 13.
5*2*2*13
260 130,2 65,2,2 13,5,2,2 2 x 2 x 5 x 13 = 260
2 x 2 x 5 x 13
Exponents are just a way of keeping track of repeated factors. The prime factorization of 260 is 2 x 2 x 5 x 13, which is 2^2 x 5 x 13 in exponent form.
2 x 2 x 5 x 13 = 2602 x 2 x 5 x 13 = 260
You need at least two numbers to find a GCF.
11 x 13 = 143 3 x 5 x 13 = 195 2 x 2 x 5 x 13 = 260
Use a factor tree. 260 130,2 65,2,2 13,5,2,2
2 x 2 x 3 x 3 x 5 x 7 = 1260