To find out how many years it will take for $5,000 to grow to $1,000,000 at a 9% annual interest rate, we can use the formula for compound interest: ( A = P(1 + r)^t ), where ( A ) is the amount of money accumulated after n years, ( P ) is the principal amount, ( r ) is the annual interest rate, and ( t ) is the number of years. Rearranging the formula to solve for ( t ) gives ( t = \frac{\log(A/P)}{\log(1 + r)} ). Plugging in the values (( A = 1,000,000 ), ( P = 5,000 ), ( r = 0.09 )), we find that it will take approximately 27.7 years for the investment to grow to $1,000,000.
Simple interest: 5000 + I = PTR/100 = 5000 + 5000 x 4 x 6/100 = 6200 Compound interest: = 5000 x 1.064 = 6312.38
0.5 x 0.01 x 1000000 = $5000
Simple interest I=Prt = (5000)(0.07)(2) = $700.Compound interest: A=P(1+r)t = 5000(1.07)2 = 5000(1.1449) = $5,724.50;I=A-P = 5,724.50 - 5000 = $724.50
5000 x 200 = 1000000
250.00.
It is 6655.
Simple interest: 5000 + I = PTR/100 = 5000 + 5000 x 4 x 6/100 = 6200 Compound interest: = 5000 x 1.064 = 6312.38
six percent
$214.68
0.5 x 0.01 x 1000000 = $5000
Depends on how often and when the interest will be paid. typicalle once a year at the end of the year. In that case 5000 * (1.05^3) = 5788.12
10795
Simple interest I=Prt = (5000)(0.07)(2) = $700.Compound interest: A=P(1+r)t = 5000(1.07)2 = 5000(1.1449) = $5,724.50;I=A-P = 5,724.50 - 5000 = $724.50
5000 x 200 = 1000000
Interest = Rs 408 so capital = 5000. So the simple interest would be 5000*4/100*2 = Rs 400.
250.00.
6 yrs @ 10% = 60% = 3000