The answer depends on the depth to which the area is covered and, to some extent, that will depend on the size of the gravel.
Area = 24 ft * 12 ft = 24*12 sq ft = 288 sq ft
4*3*6 4*3=12 4*6=24 6*3=18 12+18+24=54 54*2=108 sq ft
24 sq ft.......
72 Feet
The answer depends on the depth to which the area is covered and, to some extent, that will depend on the size of the gravel.
Area = 24 ft * 12 ft = 24*12 sq ft = 288 sq ft
4*3*6 4*3=12 4*6=24 6*3=18 12+18+24=54 54*2=108 sq ft
24 sq ft.......
The answer will depend on how fine the rock is crushed and the depth to which the area needs to be covered.
A team of 10 employees covered 472,413 miles in 24 hours on a 242-ft. 9 in. waterslide.
72 Feet
The area of a rectangle is found by multiplying its length by its width. 6 ft x 4 ft = 24 sq ft.
24 ft
24 sq. ft.
Multiply width by length to get the area. The answer would be 576 square feet.
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.