2 inches = 1/6 foot
27 cubic feet = 1 cubic yard
Volume of the hole = (15' x 7' x 1/6-ft) = 17.5 cubic feet = 0.648 cubic yard (rounded)
about 432 cubic inches
5,287.7 gallons of water.
.21 yards of sand will fill an area 115 inches by 67 inches to a depth of 2.5 inches.
22/7x6x6x6 cubic inches
None, as a hole which is 6 inches wide and 42 inches long has no depth and thus no volume.
about 432 cubic inches
18.6240 yd³
5,287.7 gallons of water.
To calculate the volume of concrete needed to fill a hole with a diameter of 12 inches and a depth of 24 inches, first convert the dimensions to feet: the diameter is 1 foot and the depth is 2 feet. The radius is 0.5 feet. Using the formula for the volume of a cylinder (V = πr²h), the volume is approximately 3.14 × (0.5)² × 2 = 1.57 cubic feet. Therefore, you need about 1.57 cubic feet of concrete to fill the hole.
To install a mailbox post correctly, dig a hole at least 24 inches deep, place the post in the hole, and fill it with concrete. Make sure the post is level and allow the concrete to set before attaching the mailbox.
.21 yards of sand will fill an area 115 inches by 67 inches to a depth of 2.5 inches.
42 cubic feet or 1.56 yards.
The recommended method for installing a concrete footing for a 6x6 post is to dig a hole that is at least 12 inches in diameter and 24 inches deep. Place a cardboard tube form in the hole and fill it with concrete, making sure it is level. Insert a post anchor into the wet concrete and allow it to cure for at least 24 hours before attaching the post.
To calculate the amount of concrete needed to fill a 12-inch diameter hole that is 18 inches deep, first convert the measurements to feet: the diameter is 1 foot and the depth is 1.5 feet. The volume of a cylinder is given by the formula V = πr²h. The radius (r) is 0.5 feet, so the volume is approximately π(0.5)²(1.5) = about 1.18 cubic feet. Thus, you would need roughly 1.18 cubic feet of concrete to fill the hole.
22/7x6x6x6 cubic inches
None, as a hole which is 6 inches wide and 42 inches long has no depth and thus no volume.
6,400 ft3