34' x 1'8" x 4'
the only tricky thing here is that 1'8" can't be multiplied right away... the 8 inches converts to 0.6667 feet, so after that you just multiply the terms
34' * 1.6667' * 4' = 226.667 Feet Cubed, or (226 Feet, and 8 Inches)
if you want inches... I'll convert everything to inches...
408" x 20" x 48"
then you just multiply them...
408" x 20" x 48"
= 391680
and since your multiplying inches, by inches, by inches, it's called cubic inches (inches^3)
None, as a hole which is 6 inches wide and 42 inches long has no depth and thus no volume.
To calculate the volume of water needed to fill a rectangular pool, multiply the length, width, and depth together. Assuming the depth is 4 feet, the volume of this pool would be 48 ft x 24 ft x 4 ft = 4,608 cubic feet of water.
If the area that needs filling is rectangular shape and the bottom of it is a consistent 7 inches you should need about 418.25 cubic feet of fill dirt. I used the formula for finding the volume of a three dimensional rectangle which is height times width times depth. Using 717 as the width times depth which is the formula for the area of a rectangle, but it would instead be called width and length. With the product of the width and depth being 717 you just have to finish the formula by multiplying 717 by the height (the depth of the hole in the ground) 0.5833... resulting in the volume of the hole in the ground which with volume is measured with a cubed unit while area is a square unit. So You would need approximately 418.25 cubic feet of fill dirt. The formula for the volume of a rectangle shaped box is on this website. http://wiki.answers.com/Q/What_is_the_formula_for_calculating_the_volume_of_a_rectangle
A hole with two dimensions has no third dimension. → its volume is 6 ft × 10 in × 0 ft = 0 ft³ → You require NO concrete to fill a hole which is given as an area as it has NO volume.
Need to know width in order to answer this.
Do length times width times depth. Orrr fill it up as much as you can :D
How much concrete is required to fill 100 cu feet
(INCHES)
None, as a hole which is 6 inches wide and 42 inches long has no depth and thus no volume.
To calculate the volume of water needed to fill a rectangular pool, multiply the length, width, and depth together. Assuming the depth is 4 feet, the volume of this pool would be 48 ft x 24 ft x 4 ft = 4,608 cubic feet of water.
1.2345 yards
That depends on what depth you want the concrete !
If the area that needs filling is rectangular shape and the bottom of it is a consistent 7 inches you should need about 418.25 cubic feet of fill dirt. I used the formula for finding the volume of a three dimensional rectangle which is height times width times depth. Using 717 as the width times depth which is the formula for the area of a rectangle, but it would instead be called width and length. With the product of the width and depth being 717 you just have to finish the formula by multiplying 717 by the height (the depth of the hole in the ground) 0.5833... resulting in the volume of the hole in the ground which with volume is measured with a cubed unit while area is a square unit. So You would need approximately 418.25 cubic feet of fill dirt. The formula for the volume of a rectangle shaped box is on this website. http://wiki.answers.com/Q/What_is_the_formula_for_calculating_the_volume_of_a_rectangle
To fill up a 12 foot swimming pool, you would need approximately 6,900 gallons of water.
It will take 72 sq. ft. of sand. Or 2.66 sq. yds. That will fill the box even.
The depth of the pour would also be necessary to calculate the volume of concrete needed.
It depends on the depth required