The question cannot be answered in any sensible way.
The weight will depend on the volume of the oak, its density and the force of gravity acting on it.
There is no information on the volume. The available information suggests that it is a 1 inch square - a 2-dimensional concept. Such an object cannot exist because no matter how thin, a square of oak MUST have a thickness and so is a three dimensional object - a cuboid (or square prism).
The density of oak will vary from sample to sample - depending, for example, on how dry it is.
Finally, the force of gravity varies by upto 5% on the surface of the earth. Up mountains and down deep mines the variation will be larger. And, taking things to an extreme, the force of gravity will be 0 at some points in space (Lagrange points and deep space) and infinitely large at others (inside black hole horizons). By suitable choice of location, an object could be made to weigh any amount you like.
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It is not possible to answer the question sensibly. Square feet are a measure of area, whereas weight is a property associated with volume. 10 sq feet of oak would probably weigh less than a feather if it were 1 micron thick. On the other hand, it would weigh a lot if it were 2 foot thick.
Depends, of course, on the density of the steel.
depend on the stone used for the gravel.
Density of loose soil is about 1200 kg/m3 1 cubic meter of soil may weigh more than this if compacted or moist.
.032 Aluminum sheet typically weighs about .45lbs per square foot. Do one square inch would be 1/144th of that, or .003lbs. A little under 1/10th of an ounce