A pipe is a cylinder.Diameter = 6 inches = 0.5 feet=> Radius = 0.25 feetHeight = 20 feetVolume of a cylinder = pi * r^2 * h square units= 3.1415 * 0.25 * 0.25 * 20 square feet= 3.926875 square feet
2*pi*radius*length measured in square units
The area of the curved part is 2*pi*r*l square units, where r is the radius of the pipe and l is the length. If the object is closed at both ends, its total area is 2*pi*r*(r + l) square units.
That depends on the material of the pipe. A lead pipe would weigh more than a plastic one. However, if you know the mass per cubic inch of the material, you can work it out, here's how you do it: Let m = the mass of one cubic inch of the material Let w = the total weight of the pipe Let l = the length of the pipe in inches then the equation you want is this: w = lmπ(r2 - (r - 0.5)2) Given that we want the weight per foot, we can say that "l", the length in inches, equals 12. We can also replace "r" with the outer radius of the pipe: w = 12mπ(302 - 29.52) w = m × 333π w ≈ m × 1046.15 Where w is the weight of the pipe, and m is the mass of the material per cubic foot.
7.07 square feet
You need to specify the wall thickness in order to calculate the weight.
A pipe is a cylinder.Diameter = 6 inches = 0.5 feet=> Radius = 0.25 feetHeight = 20 feetVolume of a cylinder = pi * r^2 * h square units= 3.1415 * 0.25 * 0.25 * 20 square feet= 3.926875 square feet
(Pi*(Center of elbow - od/2)^2-(pi*(Center of elbow+od/2)^2)รท4)รท100000=0.221 Square Meter
The weight of a square foot of muscle can vary depending on various factors such as the individual's body composition and overall muscle density. On average, muscle tissue weighs about 18-20 pounds per square foot.
It is based on the flow area, which is proportional to the square of the diameter. 2 squared = 4. 4 squared = 16. So, the 4 inch pipe can take 16/4 = 4 times the volume of the 2 inch pipe. It might be less confusing if you had picked sizes other than 2 and 4. This is a rough calculation, since pipe inside diameters are not the same as nominal sizes, but close enough for most purposes.
2*pi*radius*length measured in square units
The easiest way is to find the centerline length and multiply that by the linear weight of the pipe size being used. Alternatively, this formula should give the weight of an elbow in pounds: w=0.071*pi^2*R*(ro^2-ri^2) Where: w= weight of elbow (lb) R=curve radius of elbow (in) ro=outside radius of pipe (in) ri=inside radius of pipe (in)
This depends on the size of the copper pipe and what class it is. For example, copper pipe half inch class 0 and copper pipe class 3 have a wide weight difference because the wall of the class 3 copper pipe is much thicker.
The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.The answer will depend on whether it is a 2 inch pipe or a 2 cm pipe or a 2 foot pipe or whatever.
Surface area of an open pipe = 2*pi*radius*length or pi*diameter*length in square units.
The weight of a square foot of bronze would depend on its thickness. On average, a square foot of bronze that is 1/8 inch thick would weigh around 1.5 pounds.
The area of the curved part is 2*pi*r*l square units, where r is the radius of the pipe and l is the length. If the object is closed at both ends, its total area is 2*pi*r*(r + l) square units.