Chat with our AI personalities
8 "
To calculate the weight of a rolled steel with given dimensions, we need the density of the steel. Assuming a typical density of 7850 kg/m³, the weight can be calculated as follows: the volume of the rolled steel is (π * radius² * height) - (π * (radius - thickness)² * height). Substituting the values, the weight would be (π * (2 feet)² * 12 feet) - (π * (2 feet - 1/4 inch)² * 12 feet), which equals approximately 19,347 pounds.
The surface area of a sphere with a 24 inch diameter is 1809.6 square inches = 12.6 sq feet
If the radius is 18 feet - then the diameter is 36 feet. The circumference measurement is irrelevant !
A circle with an 8-inch diameter has a perimeter of 25.1 inches.