The whole question is Two vertical poles of height 1 yard and 2 yards are located 3 yards apart. The poles are secured by the rope going from the top of one pole to a poing on the ground between the poles and then to the top of the second pole. Where should the point on the ground be located to minimize the length of the rope. What is the minimal leght of the rope? Can someone please help
30 inches or 2 feet and 6 inches
C'mon, you cabn do this... 20X15= sq yards Grab the cell phone calculator or bust an artery & try to do it in your head... (2X 15 is easy then add the zero!!!) now you have a sq yards times the rate ($2) per yard to multiply by and again that's so easy you can doo it in your head... 300yards X $2=$???.??
3 yards, 2 feet
It is: 110/3 = 36 yards and 2 feet
56 cents
2 yards = 36 x 2 inches. So, 72 inches.72 inches - 28 inches = 44 inchesThe answer is 44 in. or 1 yd. and 8 in.
1 yard.
double the cost of 1 yard, and twice as less 4 yards...haha
The whole question is Two vertical poles of height 1 yard and 2 yards are located 3 yards apart. The poles are secured by the rope going from the top of one pole to a poing on the ground between the poles and then to the top of the second pole. Where should the point on the ground be located to minimize the length of the rope. What is the minimal leght of the rope? Can someone please help
2 miles is 3,520 yards.
Six feet in 2 yards.
30 inches or 2 feet and 6 inches
2 yards = 182.88 centimeters
18
it would be 2 yards
2 miles is 3,520 yards.