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You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state.

2.67 kg = 2670 grams

q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C)

= - 9.45 X 105 Joules

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This much heat energy must be lost to lower the temperature of the steam.

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Q: How much heat energy will be required to lower the temperature of 2.67kg of steam from 282 degrees Celsius to 105 degrees Celsius?
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Related questions

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