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Raise the temp of 52 grams of water from 33.0 C to 100 C = 52*67*4.184 = 14.577 kJConvert evaporate 52 g of water to steam without change of temp = 52*2259 = 117.468 kJ

Raise the temp of 52 grams of steam from 100 C to 110 C = 52*10*2.02 = 1.051 kJ


Total energy required = 133.095 kJ = 31,811 calories or 31.811 kCal.

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Q: How much heat is necessary to change a 52.0 gram sample of water at 33.0 degrees Celsius into steam at 110 degrees celsius?
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