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If the ice starts at 0 degrees Celsius and vaporization takes place at 100 degrees Celsius, then ... 10 lbs = 4540 grams
Q = 80(4540) + 1(100 - 0)(4540) + 540(4540)
Q = 720(4540) = 3,268,800 calories
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How much heat is required to change 0.2kg of ice at -5 degrees to water at 5 degrees?
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
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How much heat is required to convert 0.3 kilogram of ice to 0 degree celsius at the same temperature?
question makes no sense.....
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How much heat is needed to vaporize 1.25 kg of ethanol?
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How much energy is required to vaporize 2kg of water at 100c?
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