1 x 115, 5 x 23, 23 x 5, 115 x 1 = 115
1 x 115, 5 x 23, 23 x 5, 115 x 1 = 115
1 x 115, 5 x 23, 23 x 5, 115 x 1
1 x 115, 5 x 23 | 23 x 5, 115 x 1
115 = (1 x 100) + (1 x 10) + (5 x 1)
6.087
The first ten positive integer multiples of 115 are as follows: 115 x 1 = 115 115 x 2 = 230 115 x 3 = 345 115 x 4 = 460 115 x 5 = 575 115 x 6 = 690 115 x 7 = 805 115 x 8 = 920 115 x 9 = 1035 115 x 10 = 1150
1 x 115 5 x 23
If the number is x then 135*x = 115 so tat x = 115/135 = 0.851851...
You can simplify the term by approximation! Here is the approach: Let y = √x = x^(½). Then, dy/dx = ½ * x^(-½) = 1/(2√x) Select 115² to be x. Then, we obtain: y = 115 dy/dx = 1/(2 * 115) = 1 / 230 Therefore, we obtain this equation: y - 115 = 1/230 * (x - 115²) If x = 13144, then we have: y - 115 = 1/230 * (13144 - 115²) y = 1/230 * (13144 - 115²) + 115 ≈ 114.65 OR What you can do is to factor out each term by term and extract the perfect square factor out of the √. For instance: √(13144) = √(4 * 3286) = 2√3286
1 000 000 x 1 000 000 (1 million x 1 million) = 1 000 000 000 000 (1 trillion)
1/25 of 115 is 1/25 x 115 = 43/5 = 4.6