Perimeter = 2*(5 yds + 3 yds) = 2*8 yds = 16 yds
3ft/yd, 14/3=4.66.... or 4 and 2/3 yds or 4 yds and 2 ft
24 yds - (8 yds + 2 ft) = 15 yds 1 ft
8
24 yds - (3 yds x 3) - (5 yds x 2) = 24 yds - 9 yds - 10 yds = 5 yds remain
Perimeter = 2*(5 yds + 3 yds) = 2*8 yds = 16 yds
3ft/yd, 14/3=4.66.... or 4 and 2/3 yds or 4 yds and 2 ft
2 yds 2 ft + 1 yds 2 ft = 3 yds + 4 ft = 3 yds + (1 yd 1 ft) = 4 yds 1 ft
9 ft = 3 yds
Assuming you want a rectangular area, it can have any width and depth AS LONG AS width × length = 5 acres, ie width = 5 acres ÷ length.Some examples are:1 yd by 24200 yds (13¾ miles)2 yds by 12100 yds (6⅞ miles)4 yds by 6050 yds (3 7/16 miles)5 yds by 4840 yds (22 furlongs)8 yds by 3025 yds (13¾ furlongs)10 yds by 2420 yds (11 furlongs)11 yds (½ chain) by 2200 yds (10 furlongs)20 yds by 1210 yds (5½ furlongs)22 yds (1 chain) by 1100 yds (5 furlongs)25 yds by 968 yds40 yds by 605 yds44 yds (2 chains) by 550 yds (2½ furlongs)50 yds by 484 yds (22 chains)55 yds (2½ chains) by 440 yds (2 furlongs)88 yds (4 chains) by 275 yds (1¼ furlongs)100 yds by 242 yds (11 chains)110 yds (5 chains) by 220 yds (1 furlong)121 yds (5½ chains) by 200 yds½ furlong (110 yds) by 10 chains (220 yds)Historically an acre was the area of land a team of oxen could plough in 1 day and was a furrow long (furlong or 220 yds) and a chain (22 yds) wide (of the furrows). This was based on a rectangular field, but as the acre is a measure of area it can be any shape.
24 yds - (8 yds + 2 ft) = 15 yds 1 ft
8
The volume of a pyramid where its base is 2 yards by 2 yards and height is 6 yards is: 8 cubic yards.
24 yds - (3 yds x 3) - (5 yds x 2) = 24 yds - 9 yds - 10 yds = 5 yds remain
14.81 yds
2 feet.
1 acre = 4840 sq yds → 0.31 scre = 0.31 x 4840 sq yds = 1500.4 sq yds → a square with side length √(1500.4 sq yds) ≈ 38.735 yds ≈ 38 yds 2 ft, 2.5 in