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Anonymous
Clii: c 100 + l 50 + ii 2 = 152
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CLII
I = 1D = 50C = 100So 152 is CDIIImproved Answer:-It is: 152 = CLII
It is: CLII = 152
100 = C 50 = L 1 = I 152 = 100 + 50 + 1 + 1 = CLII
You have already given it in Roman numerals