Pipes are specified with inside diameter. I cannot find a conclusive reference, but it makes sense that hoses are measured in the same manner.
So if diameter is 1 inch, then radius = 0.5 inch, and cross section area = pi*r² = (3.14)*(0.5 in)² = 0.785 in², then multiply by length to get volume: V = (100 ft)*(12 in/ft)*(0.785 in²) = 942 in³. There are 231 cubic inches in 1 US gallon, so that is 4.08 US gallons.
There need not be any water at all in the hose! The capacity of the hose is 1.67 cubic feet.
you need more info than that. you will need to provide the length of the hose and the inside diameter of the hose to calculate the amount of water it will hold
The capacity of a 25 ft hose with a diameter of 3 inches is 1.23 cubic feet. That is the maximum volume of water in the hose: there need not be any!
52.3 cubic feet.
8*8*8 = 512 cubic inches.
50 feet of 2.5-inch diameter hose has a volume of: 1.7 cubic feet (12.72 liquid gallons)
A 20' length of 4-inch hose can hold approximately 0.38 gallons of gasoline per foot. Therefore, 20 feet of this hose can hold around 7.6 gallons of gasoline.
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
There need not be any water at all in the hose! The capacity of the hose is 1.67 cubic feet.
A 2.5 inch fire hose has a capacity of approximately 60 gallons per 100 ft. Therefore, a 50 ft hose would hold around 30 gallons of water.
There need not be any water at all in the hose! The capacity of the hose is 3.41 cubic feet.
NFPA 1901, Standard for Automotive Fire Apparatus - Requires pumpers to carry: * 15 feet of large soft sleeve hose or 20 feet of hard suction hose * 1200 feet of 2 ½ inch or larger supply hose * 400 feet of 1 ½ , 1 ¾, or 2 inch attack hose
you need more info than that. you will need to provide the length of the hose and the inside diameter of the hose to calculate the amount of water it will hold
A standard fire hose is 50 feet long. A hose this length with a 2-inch radius grants about 4.36 cubic feet. This volume holds 32 gallons of water.
Roughly 1 gallon for every 18 inches of hose.
A 1,850-foot long pipe with a 16-inch inside diameter has a volume of 2,580 cubic feet. In terms of liquid volume, this section of pipe can hold up to about 19,300 US gallons.
Assuming the hose has a 3 in inner diameter; the answer is 50 x 12 x 1.5^2 x pi in cubic inches. Divide the answer by 12 for cubic feet. 4241.15 cubic inches or 353.43 cubic feet.