Pipes are specified with inside diameter. I cannot find a conclusive reference, but it makes sense that hoses are measured in the same manner.
So if diameter is 1 inch, then radius = 0.5 inch, and cross section area = pi*r² = (3.14)*(0.5 in)² = 0.785 in², then multiply by length to get volume: V = (100 ft)*(12 in/ft)*(0.785 in²) = 942 in³. There are 231 cubic inches in 1 US gallon, so that is 4.08 US gallons.
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There need not be any water at all in the hose! The capacity of the hose is 1.67 cubic feet.
you need more info than that. you will need to provide the length of the hose and the inside diameter of the hose to calculate the amount of water it will hold
The capacity of a 25 ft hose with a diameter of 3 inches is 1.23 cubic feet. That is the maximum volume of water in the hose: there need not be any!
52.3 cubic feet.
8*8*8 = 512 cubic inches.