1 hour = 60 x 60 = 3600 sec 5 hours = 5 x 3600 = 18000 sec 30 min = 1800 sec Therefore 5 hours and 30 minutes = 18000 + 1800 = 19800 sec
There are 60 sec X 60 min = 3600 secs in one hours. Hence 10800 / 3600 = 108/36 = 3 hours.
60 sec = 1 minute 60 min = 1 hour 3600 sec = 1 hour one mile/sec = 3600 mph - pretty fast!
1 min = 60 sec 1 hour = 60 min = 60 × 60 = 3600 sec → 1 sec = 1/3600 hr distance = speed × time = 45 mph × 1 second = 45 mph × 1/3600 hr = 45 × 1/3600 miles = 1/80 mile = 1 chain = 22 yards = 66 feet
x= 3600a + 60b + c ( a hr x 3600 sec / hr ) + ( b min x 60 sec / min ) + c sec = x sec
60 sec/min X 60 min/hr = 3600 sec/hr
1 hour = 60 min 1 min = 60 sec 60•60=3600 sec = 1hour
2 hour = 3600 sec 5 min = 300 sec total sec in 2hr&5min= 3900
1 hour = 60 x 60 = 3600 sec 5 hours = 5 x 3600 = 18000 sec 30 min = 1800 sec Therefore 5 hours and 30 minutes = 18000 + 1800 = 19800 sec
There are 60 sec in a minute and 60 min in an hour OR 60 X 60 = 3600 sec/hr SO ... (number of seconds)/3600 = your answer
There are 60 sec X 60 min = 3600 secs in one hours. Hence 10800 / 3600 = 108/36 = 3 hours.
60 sec = 1 minute 60 min = 1 hour 3600 sec = 1 hour one mile/sec = 3600 mph - pretty fast!
1 min = 60 sec 1 hour = 60 min = 60 × 60 = 3600 sec → 1 sec = 1/3600 hr distance = speed × time = 45 mph × 1 second = 45 mph × 1/3600 hr = 45 × 1/3600 miles = 1/80 mile = 1 chain = 22 yards = 66 feet
main() { int sec=00,min=00,hr=00; printf("Enter time in seconds"); scanf("%d",&sec); if (sec<60) printf("%d :%d : %d",hr,min,sec); else if(sec>=60) min=int(sec/60); sec=int(sec%60); printf("%d: %d : %d",hr,min,sec); else if (sec>=3600) min=int(sec/60); sec=int(sec/60) hr=int(min/60); printf("%d : %d : %d",hr,sec,min); }
x= 3600a + 60b + c ( a hr x 3600 sec / hr ) + ( b min x 60 sec / min ) + c sec = x sec
Let's put it this way, 1 hour is 3600 seconds, so your answer is 5/18 of an hour, ie 16 min 40 sec.
1.5 days is 36 hours there are 3600 seconds in an hours (60 min 60 sec = 3600) so 36*3600 is the answer or 129600 seconds in 1.5 days