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Total = $4.22
To find the number of dimes, nickels, and pennies in $1.10, we can set up a system of equations. Let x represent the number of dimes, y represent the number of nickels, and z represent the number of pennies. The total value equation is 10x + 5y + z = 110 cents. Since there are no constraints on the number of coins, there are multiple solutions to this problem. One possible solution is 8 dimes, 0 nickels, and 10 pennies.
2 pennies = 2*1=2 Cents 1 dime = 1*10=10 Cents 2 nickels = 2*5=10 Cents Total = 2+10+10=22 1 quarter = 1*25=25 Cents Answer=22/25
Oh, what a happy little question! Let's see, to make 22 cents, you could use a combination of coins like 2 dimes and 2 pennies, or 1 dime, 3 nickels, and 2 pennies. There are several different ways to make change for 22 cents, so feel free to get creative and try out different combinations!
There are 18 ways to make 30 cents with any combination of pennies, nickels, dimes and quarters. Where p=pennies, n=nickels, d=dimes, q=quarters: 30p 6n 3d 5p + 5n 5p + 1q 10p + 4n 15p + 3n 20p + 2n 25p + 1n 10p + 2d 20p + 1d 5p + 1n + 2d 5p + 3n + 1d 10p + 2n + 1d 15p + 1n +1d 1n + 1q 2n + 2d 4n + 1d