To find the amount of oil needed for a 501 ratio in 5 liters of fuel, you divide the total volume by the ratio. In this case, 5 liters divided by 501 equals approximately 0.00998 liters of oil, which is about 10 milliliters. Thus, you would need roughly 10 milliliters of oil for 5 liters of fuel to achieve a 501 ratio.
40 litres of oil / 5 litres cans = 8 cans can be filled with 40 litres of oil.
If you fill the container up then Yes. Litres are a measure of volume, which remains the same regardless of what fluid or material you are describing.
A ratio is a comparison of parts in a whole. Both parts of a ratio will work out less than 1, so would never be a mixed number. eg ratio of oil to petrol of 1:25, total number of parts = 26, so fraction of oil = 1 / 26 and fraction of petrol = 25 / 26 * * * * * A ratio does not have to be a comparison of parts to a whole. It can also be in the reverse form: comparison of a whole to a part. Thus, the ratio of a year to a week (in a non-leap year) would be 365 : 7. In fractional form that would be 521/7
3 oz. per 1 gallon for a 50:1 ratio
It depends on the mixing ratio of gasoline / oil for the specific piece of equipment you will use the gas / oil mix. Most lawn equipment such as weed eaters and leaf blowers require a 32:1 mixture. Since 1 gallon of gasoline is 128 ounces, it is necessary to mix 128 ounces (or 1 US gallon) of gasoline to 4 ounces of 2 cycle oil to equal 32:1 ratio.
To achieve a 501 ratio of gas to oil, you would need 500 parts of gas for every 1 part of oil. This means if you have 500 gallons of gas, you would require 1 gallon of oil. The ratio can be scaled accordingly; for example, for 1000 gallons of gas, you'd need 2 gallons of oil.
12.8 u.s. ounces
To calculate the amount of oil needed for a 501 ratio, you would divide the total volume by the sum of the ratio parts. For a 501 ratio, there are 5 parts of oil and 1 part of another substance, making a total of 6 parts. Therefore, for every 501 ml of total mixture, you would use approximately 83.5 ml of oil (501 ml ÷ 6 parts × 5 parts = 417.5 ml of oil).
To determine the amount of oil needed for a 501 ratio when mixing with 6 gallons of gas, you divide 6 gallons by 501. This calculation shows that you would need approximately 0.01195 gallons of oil, which is about 1.5 ounces. Thus, for every 6 gallons of gas, you should add roughly 1.5 ounces of oil to achieve the correct mixture.
two stroke pre mix : say ratio of oil : petrol is 1 : 20, then say if you have 10 litres of petrol, you need to add 0.5 litres of oil
For a 501 2-stroke engine, the typical oil-to-fuel ratio is usually around 50:1. This means you would mix approximately 2.5% oil with your fuel, which translates to about 20 mL of oil per liter of fuel. However, it's always best to consult your engine's specific manual for the manufacturer's recommended oil ratio, as it can vary.
The recommended ratio for mixing 501 oil with gasoline is typically 1 ounce of oil per gallon of gas. This equates to about 0.8% oil by volume. Always check the manufacturer's instructions for specific mixing guidelines, as ratios can vary based on the engine and application.
2.56 Ounces of oil for every gallon of gas.
To mix 2-stroke oil with petrol, the standard ratio is typically 50:1, meaning 50 parts petrol to 1 part oil. For 25 litres of petrol, you would need 500 millilitres (or 0.5 litres) of 2-stroke oil. If your engine requires a different ratio, such as 40:1 or 32:1, adjust the amount of oil accordingly. Always refer to your engine's manual for the correct mixing ratio.
135ml to 5 litres of petrol.
That is 40 parts gasoline to 1 part oil.
5.5 litres with oil filter