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15 days
The answer depends on 3240 WHAT: seconds, days, years?
1 week = 7 days. You now have all the information required to answer this and similar questions.
96 x 24/20 = 116 for first 4 days and 115 for remaining 16 days
The Biochemical Oxygen Demand (BOD) of a sample is the amount of dissolved oxygen required by aerobic microorganisms to breakdown organic matter in the sample.The test is simple:Measure the Dissolved Oxygen content of the sample (a)Place in a sealed darkened bottleIncubate for 5 days at 20'CMeasure the Dissolved Oxygen content of the incubated sample (b)Generally you're using this test to analyse contaminated water, so you'll want to dilute it first - it may be that aren't enough aerobic microorganisms present to give you a measurable result, in which case you'll need to inoculate the sample with a suitable culture.The BOD of the sample = a - bBOD is expressed in mg O2/L of sample.Extra CreditGenerally you're using this test to analyse contaminated water, so you'll want to dilute it first - it may be that aren't enough aerobic microorganisms present to give you a measurable result, in which case you'll need to inoculate the sample with a suitable culture.The BOD of a diluted innoculated sample = ((a - b) - BOD of inoculated culture) * dilution factor
The time required is 24.06 days. The half life of iodine 131 is 8.02 days.
To calculate the time required for the sample to decay to 0.850, you need to determine how many half-lives have passed. Each half-life reduces the amount by half. First, find how many half-lives it takes to decay from 6.95 to 0.850. Then, multiply the number of half-lives by the half-life duration (27.8 days) to get the total time required.
10.76 days
7.64 days
The sample of radioactive isotope 131I decays over its half-life of approximately 8 days. This means that within 8 days, half of the initial amount of 131I will decay through radioactive decay.
18 grams are one fourth of the original sample mass of 72 grams. Accordingly, the half life is 6.2/4 = 1.55 days.
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
7.64 it is the half life of radon-222 multipled by 2
Radon-222 has a half-life of about 3.8 days. To calculate the time required for 200 grams of radon-222 to decay to 50 grams, you can use the formula: [N = N_0 \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}] where N is the final amount (50 grams), N0 is the initial amount (200 grams), t is the time in days, and t1/2 is the half-life. Solving for t gives around 7.6 days.
To solve this problem, you can use the formula for radioactive decay: N(t) = N0 * (1/2)^(t/T), where N(t) is the amount of the isotope remaining at time t, N0 is the initial amount, t is the elapsed time, and T is the half-life. Plugging in the values: 1.50 g = 12.0 g * (1/2)^(t/8.07), solve for t to find the time it takes for the iodine-131 to decay to 1.50 g.
The half-life of a radioisotope is the time it takes for half of the atoms in a sample to undergo radioactive decay. It is a characteristic property of each radioisotope and can range from fractions of a second to billions of years, depending on the specific isotope.
A radioactive nuclide with a half-life of 8.0252 days will decay to 0.75 of its original size in 3.33 days. AT = A0 2(-T/H) 0.75 = (1) 2(-T/8.0252) log2(0.75) = log2(2(-T/8.0252)) -0.415 = -T/8.0252 T = 3.33