132,000 cu ft = 822,206 Imperial gallons approx.
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal
The pool volume is 3.14 x 18 x 18 X 4/4 = 1017 cu ft - that's how much water you will need. 1017 cu ft = 7600 gallons
If it has a 90 degree angle in its cross-section then its volume is 0.5*4*9*15 = 270 cubic units
This question cannot be answered sensibly. A cu ft is a measure of volume, with dimensions [L3]. A pound is a measure of mass, with dimensions [M]. Basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information. As a simple mental exercise consider a cu ft of air and a cu ft of water. They will have very different weights.
20 cu cm
The water volume of Lake Michigan 1,180 cu mi (4,900 km3).
To find the Volume: (1) find the flat area (A = Pi*R²), (2) multiply the Area by the Depth/Height (V = AD). To find how much water the vessel will hold: water = 231 cu inches per gallon, or 7.481 gal per cu ft.
132,000 cu ft = 822,206 Imperial gallons approx.
Lake Huron contains 2.2309e+15 gallons of water.
One imperial gallon of water is approximately 4.546 liters in volume.
Should this question be? = What is the volume of 1 cu ft of water vapor at 100 degrees F and atmospheric pressure? = It's initial volume doesn't matter as you only want to know what its final volume is.
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal
Surface area (sq mi) :139,770,000 ; Volume (cu mi) :317,025,000 ; Percentage :97.5%
Assuming the dimensions given are inside dimensions: Find the surface area and then multiply by the depth to find the volume. A = p*r² A = 3.14*144 A = 452.16 452.16*6 = 2712.96 cu in (volume) If the question were asking how much water there is, you would proceed to calculate by finding how much water there is per cubic inch.
The pool volume is 3.14 x 18 x 18 X 4/4 = 1017 cu ft - that's how much water you will need. 1017 cu ft = 7600 gallons
If it has a 90 degree angle in its cross-section then its volume is 0.5*4*9*15 = 270 cubic units