How much water does an 18 ft round pool with 52 in deep walls hold?

Answer 1

Here's the answer, with the painfully detailed solution below:

'''8243 gallons''' (Approximately).

Note that the pool probably won't be filled right to the top of the 52in walls, so that total will be slightly less than 8243 gallons.

'''Solution'''

To figure out the volume of a round pool, we have to figure out the surface area of the pool, in square feet, and then multiply it by the depth of the pool in feet. That will give us the volume in cubic feet, which we then have to convert to gallons. Note that the pool is essentially a cylinder.

'''Pool Area'''

The area of the pool is figured out using the equation '''a = π × r^2''', where:

a is the area of the pool in square feet

π is 3.1416 (approximately) and is the ratio of the circumference of a circle to its radius.

r is the radius of the pool, which is half the diameter (18 ft / 2 = 9ft)

a = π × r^2

a = 3.1416 × (9ft)^2

a = 254.5 ft^2(approx)

'''Pool Depth'''

We now need to multiply this by the depth of the pool in feet.

'''d = 52in = 4.33ft'''

'''Pool Volume in Cubic Feet'''

So, the total volume of the pool, in cubic feet is '''Vf = a × d''', where:

Vf is the volume in cubic feet

a is the area in square feet

d is the depth in feetVf = a × d

Vf = 254.5ft^2 × 4.33ft

'''Vf = 1102 ft^3'''

'''Pool Volume in US Gallons'''

We now need to convert cubic feet to gallons. Each cubic foot contains 7.48 gallons (US). I was always surprised that a cubic foot was that large. But I digress.

Here's the answer:

The volume of the pool is:

V = 1102ft^3 × 7.48 gal / ft^3

'''V = 8243 gal(US)'''