To find the volume of water in a cylindrical tank, you can use the formula for the volume of a cylinder: ( V = \pi r^2 h ). The radius (r) is half the diameter, so it's 3 feet (6 feet / 2). The height (h) is 4 feet. Thus, the volume is ( V = \pi (3^2)(4) = \pi \times 9 \times 4 = 36\pi ) cubic feet, which is approximately 113.1 cubic feet.
7,500
cylinder 18 feet diameter x 1.5 feet deep volume = 381 cubic feet
none there is no dirt in a hole
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
261.66
7,500
There is no dirt in a hole that is 3 feet deep and six inches in diameter.
cylinder 18 feet diameter x 1.5 feet deep volume = 381 cubic feet
27
none.
40 to 50 feet
none there is no dirt in a hole
Assuming that you're referring to a cylindrical pool that has a 30 foot diameter and is evenly 10 feet deep throughout, it should hold approximately 940 gallons of water.
Assuming the 28 feet refers to the diameter of the circle, the answer is 1231.5 cubic feet, approx.
261.66
18.6240 yd³
None! If there was dirt in it then it wouldn't be a hole.