To raise water 1 foot vertically, you need approximately 0.433 pounds per square inch (psi) of water pressure. This means that for every additional foot of height, the pressure increases by about 0.433 psi. Therefore, to elevate water to various heights, you can multiply the height in feet by this value to find the required pressure in psi.
One square foot of water exerts a pressure of approximately 62.4 pounds per square foot at sea level. This is based on the weight of water, which is about 62.4 pounds per cubic foot. The pressure exerted increases with depth, following the principle that pressure is equal to the weight of the water column above the area.
Water pressure increases by approximately 0.433 pounds per square inch (psi) for every foot of vertical depth in water. However, horizontal distance does not affect water pressure; pressure remains constant horizontally at the same depth. Therefore, while pressure increases with depth, it does not change with horizontal distance in a body of water.
Depends on the height. You gain approximately 0.4 psi for every foot of elevation; so at 10 foot elevation you will have ~4 psi.
How much water do I have a 16x32 foot pool with debt of 4 foot to 6 foot
about 2 psi. (0.5 psi / foot of depth)
Raising the water level on Earth by one foot would require approximately 356,000 cubic kilometers of water.
This question is misguided. You don't need pressure, you need energy. Energy = work done = mass of water x g (acceleration due to gravity) x height raised. Pressure = force/area over which it is applied (e.g. the cross section of the water pipe.) So the pressure needed is given by P = mgh/area Be sure your value of g is in the right units for your mass and height measurements. Differential air pressure will be shown by raising the water level in, for example, a U shaped tube, where differentail pressure is applied between the two arms. Yes, to move the water, energy is used. BTW, energy equals force (weight) times distance, but you are not lifting all the water by one foot.
Assuming you mean a 14 foot by 20 foot pool, you need the following amount of water to raise it 1 inch:261.818 US liquid gallons; OR218.009 imperial (UK) gallons; OR991.089 liters
A cubic foot of water weighs approximately 62.4 pounds. This is based on the density of water, which is about 62.4 pounds per cubic foot at standard temperature and pressure. Therefore, if you're referring to just water, it would weigh this amount.
One fathom of water exerts a pressure of approximately 64 pounds per square foot, which is equivalent to 1.42 pounds per square inch.
Depends on the height. You gain approximately 0.4 psi for every foot of elevation; so at 10 foot elevation you will have ~4 psi.
If it is fresh water, and the surface is at sea level, then the pressure at the surface is 14.69 psi. As you submerge, then the pressure from the weight of the water above you is added to the air pressure above the water. For each foot that you descend, the water pressure will increase by 0.4331 psi, so at 328 feet deep, the water pressure is 142.0568 psi. Add the 14.69 psi air pressure to get 156.7468 psi.
How much water do I have a 16x32 foot pool with debt of 4 foot to 6 foot
30ft rise = 13 psi (pressure is 13 psi higher at bottom of a 30ft column that at the top). Water Pressure = .433 psi per ft for a column of water at 62 degrees F.
A pressure treated 6x6 usually weighs around 3.2 pounds per linear foot.
about 2 psi. (0.5 psi / foot of depth)
10 feet x 0.433 psi/ft = 4.33 psi at the base of the cylinder.