There are infinitely many possible answers.
Let L = any length greater than or equal to sqrt(193) feet.
and let W = 193/L
then any rectangle with length L and width W has an area of L*W = L*(193/L = 193 sq feet. And since L can have an infinite number of values, there are infinitely many solutions.
Furthermore, this is just for rectangular shapes. The area could be circular, triangular or any other shape.
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
Area = length x width Length = area/width
Length / Width
Length and width
If Length * Width = Area, then Area ÷ width = Length
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
Area = length x width Length = area/width
Length / Width
Length and width
If Length * Width = Area, then Area ÷ width = Length
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
If it's a cube then each side, length, width, and height; are sqrt(5) long.
It is 2*(Length + Width).
The width is the smaller length.
its length times width