(2000 sq. ft.) X (1 in.) X (1 ft. / 12 in.) = 167 cu. ft.(167 cu. ft.) X (1 cu. yd. / 27 cu. ft.) = 6.2 cu. yd.Full size pickup truck will hold 2 to 3 cu. yd.Tandem axle box truck will hold 10 cu. yd.
For 1 foot deep, 400 cu ft. For 3 inches deep, 100 cu ft.
That depends how big each individual bag is.
The volume of 36ft2 to a depth of 6" = 1/2ft is 36ft2 x 1/2ft = 18ft3. Each bag contains 5ft3 so 18/5 = 3.6 bags are needed to cover the area, so 4 bags would have to be purchased, with 2/5 bag left over.
1 ft = 12 in → 1 in = 1/12 ft Volume required to cover is 90 sq ft × 1 in = 90 sq ft × 1/12 ft = 7.5 cu ft → number of bags = 7.5 cu ft ÷ 0.8 cu ft/bag = 9.375 bags → you need to buy 10 bags
The answer will depend on the depth of the soil cover.
The answer you seek is printed on the bag; it should be fairly prominent.
50 pounds @ 100 pounds / cu ft = 0.5 cu ft = 864 cu ins So : sq root (864 / 2) = 20.785 inches So: will cover a square of 20.785 ins * 20.785 ins ( 1.732 ft * 1.732 ft) 2.999 sq feet area each bag (say 3 sq ft)
50 lb.
125
The answer depends on the thickness of the covering layer.
The answer will depend on the depth to which the substance is applied.
(2000 sq. ft.) X (1 in.) X (1 ft. / 12 in.) = 167 cu. ft.(167 cu. ft.) X (1 cu. yd. / 27 cu. ft.) = 6.2 cu. yd.Full size pickup truck will hold 2 to 3 cu. yd.Tandem axle box truck will hold 10 cu. yd.
You would need about 13 cu yards or about 15 tons.
For 1 foot deep, 400 cu ft. For 3 inches deep, 100 cu ft.
1 yard = 27 cu ft; 2 yard = 54 cu ft at 2 cu ft per bag, that is 54/2 = 27 bags
400 sq ft at 1 inch = 400x1/12 cu ft = 33.33 cu ft sand weighs 100 pounds per cu ft 33.33 X 100 = 3333 pounds at 50 lb per bag, that is 3333/50 = 66.7 bags