To get the answer, all you need to do is multiply Helen's age by two and then add four on the end.
(13 x 2) + 4 = 30
Helen's father is thirty years old.
2N-13
22
23
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
13 < 2n - 5 < 21
4+(2X13)
Helen has 32. Fiona has 16. Gwen has 8.
2N-13
Twice the difference between a number and thirteen can be written as 2 (b - 13) Five more than twice the difference between a number and thirteen can be written as 2 (b - 13) + 5. The algebraic expression is 2 (b - 13) + 5.
3y + (a + a) = 13
it happened twice
22
Your question makes no sense. Besides, it is impossible for two people to have ages equaling 44 when one is twice the age of the other. Those totals always equal multiple of 3, of which 44 is not one.
Your father's first cousin is your son's first cousin twice removed. Your father's second cousin is your son's second cousin, twice removed. And so forth...
23
married twice to Helen Woodford and Claire Ruth
Yes, Dr. Seuss got married twice. His first marriage was to Helen Palmer and his second marriage was to Audrey Dimond.