Richard B. Weldon Jr. is 52 years old (birthdate: September 26, 1958).
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A is 35 years old, B is 15 years old.
B. J. Armstrong is 43 years old (birthdate: September 9, 1967).
Lets say something called A is 8 years old. Well, if B was "twice as old" B would be 16 years old
John is 36, Jane is 27 When he was 27, she was 18. The algebraic solution to the equation: Let A = John and B = Jane, and time t = A - B (difference in ages) If t years ago, John was twice as old A = 2 (B - t) and substitute A - B for t A = 2B - 2A + 2B 3A = 4B A = 4/3 B and since A + B = 63 4/3 B + B = 63 7/3 B = 63 B = 21 and A = 28
Write and solve two simultaneous equations. a = Mary's age b = Mike's age Age now: b = 3a Age in 4 years: b + 4 = 2(a + 4)