That is an impossible question it could be any size the length of the shadow is dictated by the angle if the light source.
15 feet high
To determine the height of the tree based on the shadow length, we can use the concept of similar triangles. If the tree casts a shadow of 1 foot while a 1-foot pole also casts a shadow of 1 foot, then the height of the tree is the same as the height of the pole. Thus, the tree is also 1 foot tall.
x/85 = 6/17 30 ft.
3
2
15 feet high
121.3yd
63 feet
Assuming the two poles are parallel . Then use Similar Triangles. 27/18 is to 63/x Equating 27/18 = 63/x Algebraically rearrange x = (63/27) X 18 Cancel down (reduce) by '9' x = (63/3) X 2 Cancel down (reduce by '3') x = (21/1) X 2 x = 42/1 = 42 ft. (Which is the length of the shadow created by the 63 ft. pole).
A 1 foot shadow I think.
To determine the height of the tree based on the shadow length, we can use the concept of similar triangles. If the tree casts a shadow of 1 foot while a 1-foot pole also casts a shadow of 1 foot, then the height of the tree is the same as the height of the pole. Thus, the tree is also 1 foot tall.
x/85 = 6/17 30 ft.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
3
2
4 is to 6 as 5 is to X. 4/6 = 5/X. X = 7.5 feet.
48