length *width*height=area of cuboid
It depends on whether they are stuck together so as to form a 1x1x6 cuboid or a 1x2x3 cuboid, or a 1x1x2 cuboid on top of a 1x2x2 cuboid. Each of these will give a different answer.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
The total area of all the faces of the cuboid, because it is three dimensional it has six faces instead of just one like a normal rectangle has.
Make it infinitesimally small.
length *width*height=area of cuboid
derivation of surface area of cuboid
A cuboid is a 3 dimensional object and 3 measures are required for the total surface area of a cuboid.
Volume of a cuboid = cross-section area times its length
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
A cuboid is a hexahedron. That is a solid face with six faces. More specifically, all six faces of a cuboid are rectangular. The total surface area of a cuboid with sides of length A, B and C is 2*(AB + BC + CA) sq units.
2[l+w+h]
It depends on whether they are stuck together so as to form a 1x1x6 cuboid or a 1x2x3 cuboid, or a 1x1x2 cuboid on top of a 1x2x2 cuboid. Each of these will give a different answer.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
With great difficulty because more information about the dimensions of the cuboid are required.
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
The total area of all the faces of the cuboid, because it is three dimensional it has six faces instead of just one like a normal rectangle has.