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In rectangle ABCD, diagonals AC and BD meet at E. Angles BAC and DCA are alternate (since AB and DC are parallel) and are therefore equal. The same is true of angles ABD and CDB. Also, AB = DC, so that triangles ABE and CDE are congruent. Thus, |AE| = |EC| and |BE| = |ED|, that is, the point E bisects both AC and BD.
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Earn +20 ptsQ: How to Prove the diagonals of a rectangle bisect each other?
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In a rectangle the diagonals are?
The diagonals are equal and they bisect each other.
Does a rectangle have diagonals that bisect each other?
Yes.
Do diagonals of rectangle bisect each other?
Yes
Do the diagonals of a rectangle always bisect each other?
yes
What is a quadrilateral with diagonals that bisect each other?
The diagonals of any parallelogram (square, rhombus, rectangle, rhomboid) bisect each other. The difference is the the diagonals are equal in length for a square and rectangle, and not equal for a rhombus or rhomboid (oblique diamond).
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