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To find percent composition, you must work with the atomic masses. Look on a periodic chart to find the atomic masses of F and Na. You will find that Na has an Atomic Mass of 22.990 grams per mole of Na and that F has an atomic mass of 18.998 grams per mole of F.
So, add these both together, and that will tell you how much mass NaF will be. NaF will have a mass of 41.988 grams per mole of NaF.
Now to take the percent composition of F in NaF, simply divide the mass of F by the mass of NaF. That will give you [18.998/41.988]=.452 which will be about 45%.
So your answer is that F has a 45% composition of NaF.
PS: Since Na and F only had a stoichiometry of 1 (meaning there is 1 Na and 1 F in the molecule), no multiplication of the atomic masses was necessary when calculating the total mass of the molecule.
What else can I help you with?
Is The composition of an odd function and an odd function even?
The composition of two odd functions is an even function. If ( f(x) ) and ( g(x) ) are both odd, then for their composition ( (f \circ g)(x) = f(g(x)) ), we have ( (f \circ g)(-x) = f(g(-x)) = f(-g(x)) = -f(g(x)) = -(f \circ g)(x) ). Thus, ( (f \circ g)(x) ) satisfies the definition of an even function.
Is 40 percent a f?
Unless graded on a curve, 40% is a F.
What is a 65 percent in a letter grade?
this is a F
How do you calculate Celsius to farnhiet?
C to F: C=(5/9)(F-32) F to C: F=(9/5)C+32
What do you need to compose two functions in solving problems with composition?
To compose two functions, you need two functions, typically denoted as ( f(x) ) and ( g(x) ). The composition of these functions is expressed as ( (f \circ g)(x) ), which means you first apply ( g ) to ( x ) and then apply ( f ) to the result of ( g(x) ). Additionally, you need to ensure that the output of the second function ( g(x) ) is within the domain of the first function ( f ) for the composition to be valid.
Can you calculate the molarity of F in a 250.0 mL solution containing 18.34 g LiF and 4.32 g NaF?
First, calculate the number of moles of LiF and NaF. Then, add the moles of F from both compounds and convert it to molarity by dividing by the total volume of the solution in liters. Remember to account for the stoichiometry of each compound to determine the moles of F.
How many moles of fluoride ions are present in 10.4 g of NaF?
To calculate the number of moles of fluoride ions present in 10.4 g of NaF, you first need to determine the molar mass of NaF, which is 41 g/mol. Then, divide the given mass by the molar mass to find the number of moles of NaF (0.253 moles). Since there is one fluoride ion per molecule of NaF, there are also 0.253 moles of fluoride ions in 10.4 g of NaF.
Is NaF a salt?
Yes, NaF is a salt composed of the elements sodium (Na) and fluorine (F). It is known as sodium fluoride.
How many metal atoms are in NaF?
none its two ions one of which (Na) comes from a metal
Formula for sodium flouride?
Fluoride ion is symbolised by F- .(Mind the spelling of flUOride, it is not flouride)
What is the mass in grams of 1.00 mole of sodium fluride NaF?
To find the mass of 1.00 mole of sodium fluoride (NaF), you need to calculate its molar mass. Sodium (Na) has an atomic mass of approximately 23.0 g/mol, and fluorine (F) has an atomic mass of about 19.0 g/mol. Therefore, the molar mass of NaF is 23.0 g/mol + 19.0 g/mol = 42.0 g/mol. Thus, the mass of 1.00 mole of NaF is 42.0 grams.
Is NaF acidic basic or a salt?
It is BASIC because, if combined with water, it produces a strong base: NaOH
Why is an aqueous solution of NaF basic?
NaF is a salt composed of sodium cation (Na+) and fluoride anion (F-). When NaF dissolves in water, it hydrolyzes to form NaOH and HF. The NaOH produced in this reaction is a strong base, resulting in the aqueous solution of NaF being basic.
How many non metal atoms are in naf?
In sodium fluoride (NaF), there is 1 non-metal atom, which is fluorine (F). Sodium (Na) is a metal atom.
Is Naf a Lewis acid or Lewis base?
NaF is a Lewis base. the F- ion has electron pairs that it can donate for bonding.
What is the chemical formula for Sodium and Flourine?
Sodium- Na Fluorine- F Together- NaF
What is the electronegativity value of NaF?
Electronegativity is a property of individual elements, not compounds. In sodium fluoride (NaF), sodium (Na) has an electronegativity of approximately 0.93, while fluorine (F) has a much higher electronegativity of about 3.98 on the Pauling scale. The large difference in electronegativity between Na and F (around 3.05) indicates that the bond in NaF is highly ionic.
