To find percent composition, you must work with the atomic masses. Look on a periodic chart to find the atomic masses of F and Na. You will find that Na has an Atomic Mass of 22.990 grams per mole of Na and that F has an atomic mass of 18.998 grams per mole of F.
So, add these both together, and that will tell you how much mass NaF will be. NaF will have a mass of 41.988 grams per mole of NaF.
Now to take the percent composition of F in NaF, simply divide the mass of F by the mass of NaF. That will give you [18.998/41.988]=.452 which will be about 45%.
So your answer is that F has a 45% composition of NaF.
PS: Since Na and F only had a stoichiometry of 1 (meaning there is 1 Na and 1 F in the molecule), no multiplication of the atomic masses was necessary when calculating the total mass of the molecule.
Unless graded on a curve, 40% is a F.
this is a F
C to F: C=(5/9)(F-32) F to C: F=(9/5)C+32
border line of a D and a F
It depends on the degrees of freedom for the f-test.
First, calculate the number of moles of LiF and NaF. Then, add the moles of F from both compounds and convert it to molarity by dividing by the total volume of the solution in liters. Remember to account for the stoichiometry of each compound to determine the moles of F.
To calculate the number of moles of fluoride ions present in 10.4 g of NaF, you first need to determine the molar mass of NaF, which is 41 g/mol. Then, divide the given mass by the molar mass to find the number of moles of NaF (0.253 moles). Since there is one fluoride ion per molecule of NaF, there are also 0.253 moles of fluoride ions in 10.4 g of NaF.
Yes, NaF is a salt composed of the elements sodium (Na) and fluorine (F). It is known as sodium fluoride.
In NaF, there is one Na atom and one F atom. So, there is a total of one metal atom in NaF.
The chemical formula for sodium fluoride is NaF. It is composed of one sodium (Na) atom and one fluoride (F) atom.
NaF is a salt, specifically an ionic compound formed from a metal (sodium) and a non-metal (fluorine). In solution, NaF dissociates into Na+ and F- ions.
NaF is a salt composed of sodium cation (Na+) and fluoride anion (F-). When NaF dissolves in water, it hydrolyzes to form NaOH and HF. The NaOH produced in this reaction is a strong base, resulting in the aqueous solution of NaF being basic.
In sodium fluoride (NaF), there is 1 non-metal atom, which is fluorine (F). Sodium (Na) is a metal atom.
Sodium- Na Fluorine- F Together- NaF
Naf is a Lewis acid because it is a compound formed by the combination of sodium (Na+) cation, which can act as an electron pair acceptor.
The ionic compound formed when sodium (Na) and fluorine (F) react is sodium fluoride, with the chemical formula NaF. In this compound, sodium (Na) donates an electron to fluorine (F) to form an ionic bond between the positively charged Na+ ion and the negatively charged F- ion.
Yes, NaF contains an ionic bond. In this molecule, sodium (Na) donates an electron to fluorine (F) to form Na+ and F- ions, which are held together by electrostatic attraction, creating an ionic bond.