draw it out for ease.
data:
ab + 2 = ac
bc-1 = ac
therefore ab +2 = bc - 1
ab - bc = -3
perimeter is 62. /3 as most values are small difference. average distance is ~21.
ab is smallest, guess it is 19. if so, ac would be 21. bc would be 22. does this add up?
it actually does. i guess there is a mathematical way of doing this other than trial and error like the way i just did it, but i cannot see it right now
There are many lengths that can be used to make triangles. Basically take the longest side, add the two shorter sides together, it can be a triangle as long as the 2 shorter sides added together are longer than the longest side.
No. For a right angle triangle, the sum of the squares of the shorter sides equals the square of the longer side (the hypotenuse): 22 + 62 = 40 72 = 49
Add together the lengths of the 4 sides, or you could add the length of one shorter side to one longer side and then double it. e.g. Perimeter of parallelogram = l = b = l = b, or 2(l + b)
The length of the longer leg equals the length of the shorter leg times the square root of three.
The short side will be opposite the 30 degree angle. The longer leg is 10*sqrt(3) = 17.32 and the hypotenuse is 20.
For a triangle to exist, the sum of the shorter two sides must be longer than the third side.
There are many lengths that can be used to make triangles. Basically take the longest side, add the two shorter sides together, it can be a triangle as long as the 2 shorter sides added together are longer than the longest side.
No. For a right angle triangle, the sum of the squares of the shorter sides equals the square of the longer side (the hypotenuse): 22 + 62 = 40 72 = 49
Yes that is possible. To check, you add the two shorter sides, and they should be longer than the longest side.
The length of the longer leg of a right triangle is 3ftmore than three times the length of the shorter leg. The length of the hypotenuse is 4ftmore than three times the length of the shorter leg. Find the side lengths of the triangle.
The perimeter is the sum of all of the sides of the triangle. If the shorter leg is x, the longer leg is 3x. The hypotenuse is then the square root of x^2 + 3x^2, or 2x. Then the perimeter is x + 3x + 2x, simplified, f(x) = 6x.
Add together the lengths of the 4 sides, or you could add the length of one shorter side to one longer side and then double it. e.g. Perimeter of parallelogram = l = b = l = b, or 2(l + b)
The length of the longer leg equals the length of the shorter leg times the square root of three.
Length of longer leg = 9.4 tan 60 = 16.28 feet Length of hypotenuse = 9.4 ÷ cos 60 = 18.8 feet Perimeter of triangle = 9.4 + 16.28 + 18.8 = 44.48 feet
The short side will be opposite the 30 degree angle. The longer leg is 10*sqrt(3) = 17.32 and the hypotenuse is 20.
The dimensions given are a classic example of Pythagoras' Theorem for finding the lengths of the three sides of a right angled triangle: 52 = 42+32 So the answer your looking for is that the shorter leg is 3 feet long.
The minimum perimeter is when the triangle is an equilateral triangle. The perimeter of any other triangle with the same area will be longer. In the case of an equilateral triangle area = (√3)/4 × side² → side = √(4×6.5 cm²/√3) → perimeter = 3 × side = 3 × √(4×6.5 cm²/√3) ≈ 11.62 cm → The triangle has a perimeter greater than or equal to approx 11.62 cm.